Calculate σ(n), the sum of all positive divisors of an integer n, including 1 and n itself.
Calculate σ(n), the sum of all positive divisors of an integer n, including 1 and n itself.
Enter a positive integer
If n = p₁^a₁ × p₂^a₂ × ... × pₖ^aₖ, the sum of divisors is the product of (p^(a+1) - 1)/(p - 1) for each prime factor.
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If n = p₁^a₁ × p₂^a₂ × ... × pₖ^aₖ, the sum of divisors is the product of (p^(a+1) - 1)/(p - 1) for each prime factor.
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